Question

a ball of mass 0.30kg is thrown vertically upwards with an initial velocityog 10ms-1 . calculate the maximum potential energy it gains as it goes up.
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Answer 1

K.E=

2

1

×m×v

2

K.E=0.5×0.2×20×20=40J

As it has 40 J at initial point as total energy, at some point X,P.E is maximum.

Total energy=P.E+K.E

40=P.E+K.E

As energy is conserved, total energy at point X also must be 40 J. For P.E to be maximum K.E must be zero.

Hence P.E=40J

We can come to the conclusion that it will have the maximum value at maximum height.

Answer 2

Answer:

12.651 integral parts decimal fractions