Question

A ball of mass 0.4 kg is thrown vertically upwards
with a velocity of 14 m/s, Calculate its kinetic energy and Potential energy
after 1 second.​

Answer 1

Explanation:

Answer :-

\boxed{answer = 76 j}

answer=76j

v = u + at

.

= 14+10×1

.

=24m/s

.

\implies \bf \: ke = \frac{1}{2} mv {}^{2}⟹ke=

2

1

mv

2

\begin{gathered} \\ \end{gathered}

\implies \bf \: \frac{1}{2} \times 0.4 \times 24⟹

2

1

×0.4×24

\begin{gathered} \\ \end{gathered}

\bf \: 115.2 \: j115.2j

\implies \bf \: s = ut + \frac{1}{2} at {}^{2}⟹s=ut+

2

1

at

2

\begin{gathered} \\ \end{gathered}

\bf \: = 14 \times 1 + \frac{1}{2} \times 10 \times 1 {}^{2}=14×1+

2

1

×10×1

2

\begin{gathered} \\ \end{gathered}

\implies \bf \: 14 + 5 = 19m⟹14+5=19m

\begin{gathered} \\ \end{gathered}

\implies \bf \: e = mgh = 0.4 \times 10 \times 19 = 76 \: j⟹e=mgh=0.4×10×19=76j

\begin{gathered} \\ \end{gathered}

\boxed{answer = 76 j}

answer=76j