Physics, asked by taslim18061, 11 months ago

A ball of mass 0.4kg is thrown vertically upward with a velocity of 14 m/s . Calculate its kinetic energy and potential energy after 1 second

Answers

Answered by raopragathi100
1

Answer:

K.E is 39.2 m/s

P.E is 4m/s

Explanation:

Answered by BlastOracle
7

Answer :-

\boxed{answer = 76 j}

v = u + at

.

= 14+10×1

.

=24m/s

.

\implies \bf \: ke =  \frac{1}{2} mv {}^{2}

 \\

\implies \bf \:  \frac{1}{2}  \times 0.4 \times 24

 \\

\bf \: 115.2 \: j

\implies \bf \: s = ut +  \frac{1}{2} at {}^{2}

 \\

\bf \:  = 14 \times 1 +  \frac{1}{2}  \times 10 \times 1 {}^{2}

 \\

\implies \bf \: 14 + 5 = 19m

 \\

\implies \bf \: e = mgh = 0.4 \times 10 \times 19 = 76 \: j

 \\

\boxed{answer = 76 j}

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