A BALL OF MASS 0.5 KG DROPPED FROM A HEIGHT. WHAT IS THE WORK DONE BY ITS WEIGHT IN TWO SECONDS AFTER THE BALL IS DROPPED
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Given:-
Mass = 0.5kg
Time = 1 sec
Since
F = mg
F = 0.5*9.8
= 4.9N
Displacement in 1 sec = 9.8m
As acceleration will be 9.8ms^-2
We know
W = F* D
= 4.9*9.8
=48.02J
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