A ball of mass 0.5 kg is dropped from a height of 5m.(a) find the kinetic energy of the ball just before it reaches the ground.(b) what is its speed at this instance?
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Answer:
Step-by-step explanation:
Kinetic energy=stored potential energy
=mgh
= 0.5*10*5
=25 Joule
25=1/2*m*v²
50/0.5=v²
100=v²
v=10m
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