Question

A ball of mass 0.5 kg is thrown normally against
a wall at a speed of 12 ms 1. It bounces back
normally with a speed of 8 ms-1. The collision
lasts for 0.10 s. What is the average force on the
ball due to the collision?
(a) 0.2 N
(b) 1 N
(c) 20 N
(d) 100 N

Answer 1

Answer:

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Explanation:

Solving for the change in momentum of the body

initial momentum = mass * initial velocity

initial momentum = 0.5 kg * 12 m/s = +6.0 kg x m/s

final momentum = mass * final velocity

final momentum = 0.5 kg * -8 m/s = -4.0 kg x m/s

Change in momentum = +6.0 kg x m/s - (-4.0 kg x m/s) = +10 kg x m/s

Solving for the average force

Impulse = change in momentum

Force * time = +10 kg x m/s

Force = +10 kg x m/s / 0.1s

Force = 100 kg x m/s^2 = 100 N

The average force received by the body is 100 N