Question

A ball of mass 0.5 kg moving with a speed of 2.0 m/s
strikes a rigid wall in a direction perpendicular to
the wall and is reflected back after a perfectly elastic
collision. If the ball has remained in contact with the
wall for 0.5 s, calculate the average force exerted on
the ball by the wall.
​

Answer 1

Answer:

2 Newtons of force

Explanation:

Momentum of ball = 0.5 × 2 = 1 kg m/s

Impulsive time { time of contact between ball and wall}

= 0.5 sec

force applied = momentum ÷ impulsive time

1 ÷ 0.5 = 2 kg m/ sec squre