Question

A ball of mass 0.5 kg, moving with velocity
(21 +2j) m/s, is caught by a fielder. If the ball
comes to rest in 1.414 s, then the magnitude of
average force applied on the ball is (1)2N(2) 1/2N
(3) 4N
(4) 1 N​

Answer 1

1)2N

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Answer 2

Answer:

(4)1N

Explanation:

m=0.5

u=2i+2j

v=0(Since it comes to rest)

t=1.414

therefore, a=v-u/t =-2i-2j/1.414

F=ma=(1/2)*(-2i-2j/$\sqrt{2\\}$)  

|F|=1N {On solving}