A ball of mass 0.500kg is attached to the end of a cord 1.50m long. The ball is whirled in a horizontal circle as shown in fig.If the cord can withstand a maximum tension of 50.0N, What is the maximum speed at which the ball can be whirled before the cord breaks ? Assume that the string remains horizontal during the motion.
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A ball of mass 0.500kg is attached to the end of a cord 1.50m long. The ball is whirled in a horizontal circle as shown in fig.If the cord can withstand a maximum tension of 50.0N, What is the maximum speed at which the ball can be whirled before the cord breaks ? Assume that the string remains horizontal during the motion.
12.2m/s3.5m/s4.8m/s2.9m/s
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Answer : 12.2m/s
The force causing the centripetal acceleration in this case is the force T exerted by the cord on the ball, Solving for v, we have
T=mv2r
v=Trm−−−√
vmax=TmaxTm−−−−−√
=(50.0N)(1.50m)0.500kg−−−−−−−−−−−−−√
=12.2m/
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