Question

a ball of mass 0.5kg is thrown up with velocity 10m/s. find the height upto which it will reach and it's potential energy. take g = 10​

Answer 1

Mass =0.5kg

Velocity (u)= 10m/s

Maximum height =u²/2g = 100/2×10 =5m.

The potential energy =mgh =0.5×10×5=25J(Ans)

Answer 2

$\Large{\underline{\underline{\red{\sf{Answer :}}}}}$

$\large{\underline{\boxed{\sf{Height \: = \: 5 \: m }}}}$

$\large{\underline{\underline{\red{\sf{Step-By-Step-Explanation :}}}}}$

$\displaystyle {\sf{Given \begin{cases} Mass \: (m) \: = \: 0.5 \: kg \\\\ Velocity \: (v) \: = \: 10 \: ms^{-1} \\\\ Gravitational \: force \: (g) \: = \: 10 \: ms^{-2} \end{cases}}}$

We have formula for Kinetic energy

$\Large \displaystyle{\boxed{\boxed{\sf{K.E \: = \: \frac{1}{2} \: mv^2}}}}$

Put Values

$\rightarrow {\sf{K.E \: = \: \frac{1}{2} \: (0.5) \: \times \: (10)^2}}$

$\rightarrow {\sf{K.E \: = \: \frac{1}{\cancel{2}} \: (0.5) (\cancel{100})}}$

$\rightarrow {\sf{K.E \: = \: (0.5)(50)}}$

$\implies {\boxed{\boxed{\sf{K.E \: = \: 25 \: J}}}}$

___________________________

In this case Kinetic Energy is equal to Potential Energy

So,

K.E = P.E = 25 J

Formula for Potential Energy is :

$\Large{\boxed{\boxed{\sf{P.E \: = \: mgh}}}}$

Put Values

$\rightarrow {\sf{25 \: = \: (0.5)(10)(h)}}$

$\rightarrow {\sf{25 \: = \: 5h}}$

$\rightarrow {\sf{h \: = \: \frac{25}{5}}}$

$\LARGE{\boxed{\boxed{\red{\sf{h \: = \: 5 \: m}}}}}$