Question

A ball of mass 0.6 Kg attached to a light inextensible string rotates in a vertical circle of radius 0.75 m such that it has a speed of 5 m/s, when the string is horizontal. Tension in the string, when it is horizontal on other side is (g = 10 m/s2 )

Answer 1

on other side also it will be 5mps by work energy theorem
when it is horizontal the gravity force will not affect tension as they are perpendicular.
tension T = centrifugal force = mv^2/r = 0.6*25/0.75=20 N

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Answer 2

Answer:

20N

Explanation:

As they are asking tension at horizontal there will be no weight component only force acting on the body is centrifugal force given by mv^2/r

So Tension(T) =mv^2/r

=0.6(5)^2/0.75

=0.6(25)/0.75

=15/0.75

=20N

THEREFORE TENSION IN STRING IS 20N.

FOR DIAGRAM REFER TO ATTACHMENT.

I hope you are satisfied by my answer.