Question

A ball of mass 06.kg attached to a light inextensible string rotates in a vertical circle of radius 0.75m such that it has speed of 5 m/sec when the string is horizontal. Tension in the string when it is horizontal on the other side is (g= 10m/sec²)
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Answer 1

Answer:

M = 2.50 kg

T = 200 N

l = 20.0 m

Mass per unit length, μ=M/l=2.50/20=0.125Kgm

−1

The velocity (v) of the transverse wave in the string is given by the relation:

v=

T/μ

=

200/0.125

=

1600

=40 m/s

∴ Time taken by the disturbance to reach the other end,

t=l/v=20/40=0.5s

Explanation:

M = 2.50 kg

T = 200 N

l = 20.0 m

Mass per unit length, μ=M/l=2.50/20=0.125Kgm

−1

The velocity (v) of the transverse wave in the string is given by the relation:

v=

T/μ

=

200/0.125

=

1600

=40 m/s

∴ Time taken by the disturbance to reach the other end,

t=l/v=20/40=0.5s