A ball of mass 1 kg is dropped from 20 m height find velocity of ball after second collision
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A ball of mass 1kg is dropped from 20 m height. The velocity after second collision is 20 m/s
1) In the given problem there is no mention of air resistance which may hinder the path of the bouncing ball and reduce its velocity.
2) So, it would bounce with the same velocity as that of the first collision.
3) Velocity after first collision is
v = √(2*g*h)
4) Therefore the velocity is given as v = √( 2*10*20) = 20m/s
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