Question

a ball of mass 1 kg is dropped from 20 m height on ground and it rebounds to height 5 m. Find magnitude of change in momentum during its collision with the ground. [take g= 10 m/s^2]

Answer 1

Answer:

30

Explanation:

momentum=mass×velocity

m=m×v

m=1×v

v²=u²+2as

=0+2(10)(20)

=20×20

v² =400

v=20

m1=1×20=20

m2=m×v

m=1×v

v²=u²+2as

=0+2(-10)(5)

=2(-50)

v² =(-100)

v=-10

m2=1×-10

m2=-10

the difference between their magnitude =20-(-10)

=20+10

=30

Ans=30