Question

A ball of mass 1 kg is moving with the velocity of 10 m/s.if it comes to rest after travelling a distance of 30m. Then find the the force of friction between the ball and floor.
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Answer 1

v²-u²=2as

where, v is final velocity

u is initial velocity

a us acceleration

s is distance

=> (0)²-(10)²=2a30

=> -100=60a

=>a= -5/3m/s²

here minus indicates, acceleration is decreasing or deceleration

F=ma

=(1)(5/3)

=5/3J

Answer 2

Answer:

16.6 N

Explanation:

According to Equations of motion,

v^2 - u^2 = 2as

As v = 0 because it finally came to rest.

u = 10m/s (given)

s (distance travelled) = 30m

Now,

0^2 - 10^2 = 2×a×30

0 - 100 = 60 × a

-100 = 60 × a

-100/60 = a

- 16.6 = a

Now we know ,

F = ma

F = 1 kg × (-16.6)

F = -16.6 N