Question

A ball of mass 1 kg is projected with a velocity of 20√2 m/s from the origin of an xy co-ordinate axis system at an angle 45° with x-axis (horizontal). The angular momentum [In SI units) of the ball about the point of projection after 2 s of projection is (take g = 10 m/s) (y-axis is taken as vertical) (1) - 400 K (2) 200 i 3) 300 j (4) - 350 j (

Answer 1

formula:

time taken to reach the highest point in projectile motion is ( 1) as given in image soln Tm=time to reach max height...

Explanation:

u= initial velocity

deta= Angle with x axis...

From Tm value(refer image) we know that 2 sec taken to reach maximum height....

Also, we know in projectile motion horizontal component of velocity remains the same....(2)

Hope, it is helpfull.....