Question

A ball of mass 1 kg is thrown at 20 metre per second at an angle 30° what will be the momentum of the ball at the top most point of projectile?​

Answer 1

Answer:

since momentum is equal to product of mass and velocity

p=m*v

p=1*20

p=20

Answer 2

The momentum of the ball at the top most point of projectile is 17.32 kg-m/s.

Explanation:

Mass of the ball, m = 1 kg

Initial speed of the ball, u = 20 m/s at an angle of 30°

The product of mass and velocity is called momentum of an object.

Initial velocity in vector form is given by :

$u=vcos30i+vsin30j$

Final velocity,

$v=vcos30i$ (y component is 0)

So, the momentum of the ball at the top most point of projectile is :

$p=mv$

$p=1\times vcos(30)$

$p=1\times 20cos(30)$

p = 17.32 kg-m/s

So, the momentum of the ball at the top most point of projectile is 17.32 kg-m/s. Hence, this is the required solution.

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