A ball of mass 1 kg is thrown vertically upward with speed of 30 m/s. Find the potential energy when it is at half of the maximum height. (take g= 10m/s)
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2gs = v^2-u^2
2×10×s = 30^2-0^2
20×s =900-0
s=900/20
s=45
PE = mgh
PE = 1×10×45/2
PE=5×45
PE= 225J
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