A ball of mass 10 g is moving with a velocity of
50 m s-1. On applying a constant force on ball for
2.0 s, it acquires a velocity of 70 m sl. Calculate:
(i) the initial momentum of ball,
(ii) the final momentum of ball,
(iii) the rate of change of momentum,
(iv) the acceleration of ball, and
(v) the magnitude of force applied.
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Answer:
according to me the mass of the ball should be 10 kg and here is the answer:
m = 10 kg u = 50 m/s v = 70 m/s t = 2s a = ? F = ? (a) Pi = m•u . = (10•50)kg m/s . = 500 kg m/s (b) Pf = m•v . = (10•70) kg m/s . = 700 kg m/s (c) a = (v-u)/t . = 10 m/s² (d) F = m•a . = 50kg x 10m/s² . = 500 kg m/s² . = 500N .
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