A ball of mass 10 g is moving with a velocity of 50 m/s. On applying a constant force on ball for 2.0s,it acquires a velocity of 70 m/s, Calculate: (i) The initial momentum of ball (ii) The final momentum of ball (iii) The magnitude of force applied (iv) Rate of change of momentum I want answers not steps Please help fast it is urgent
Answers
Answered by
0
Answer:
m = 10 kg u = 50 m/s v = 70 m/s t = 2s a = ? F = ? (a) Pi = m•u . = (10•50)kg m/s . = 500 kg m/s (b) Pf = m•v . = (10•70) kg m/s . = 700 kg m/s (c) a = (v-u)/t . = 10 m/s² (d) F = m•a . = 50kg x 10m/s² . = 500 kg m/s² . = 500N .
Please mark me as the brainliest
Similar questions