Question

A ball of mass 10 g is moving with a velocity of
50 m sl. On applying a constant force on ball for
2.0 s, it acquires a velocity of 70 msl. Calculate :
(i) the initial momentum of ball,
(ii) the final momentum of ball,
(iii) the rate of change of momentum,
(iv) the acceleration of ball, and
(v) the magnitude of force applied.​

Answer 1

Answer:

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Explanation:

Here is your answer

Answer 2

A ball of mass 10 g is moving with a velocity of 50 m s. On applying a constant force on ball for2.0 s, it acquires a velocity of 70 m/s.

As per the given data ,

mass of the ball= 10 g = 0.01 kg

initial velocity of the ball = 50 m / s

time for which the force is applied = 2 s

final velocity of the world = 70 m / s

_________________

(i) the initial momentum of ball

mass of the ball= 10 g = 0.01 kg

initial velocity of the ball = 50 m / s

initial momentum of the ball

= mass × initial velocity

= 0.01 × 50

= 0.5

initial momentum of the ball = 0.5 kg m/s

___________________

(ii) the final momentum of ball

mass of the ball= 10 g = 0.01 kg

final velocity of the ball = 70 m / s

final momentum of the ball

= mass × final velocity

= 0.01 × 70

= 0.7

initial momentum of the ball = 0.7 kg m/s

_____________________

(iii) the rate of change of momentum

$\mathtt{ = \dfrac{P_f - P_i}{t} }$

$\mathtt{ = \dfrac{mv - mu}{t} }$

$\mathtt{ = \dfrac{0.7 - 0.5}{2} }$

$\mathtt{ = \dfrac{0.2}{2} }$

$\mathtt{ = 0.1}$

____________________

(v) the magnitude of force applied.

We know that ,

rate of change of momentum = force

force applied = 0.1 N

___________________

(iv) the acceleration of ball

we know that ,

$\rightarrow\mathtt{ F = ma }$

$\rightarrow\mathtt{ a = \dfrac{F}{m} }$

$\rightarrow\mathtt{ a = \dfrac{0.1}{0.01} }$

$\rightarrow\mathtt{ a = 10 \dfrac{m}{ {s}^{2} } }$

The acceleration of the ball is 10 m /s²