Question

a ball of mass 10 gram is moving with a velocity of 5 metre per second on applying a constant force on the ball for 2 second it acquires a velocity of 70 MS calculate 1. the initial momentum of wall 2.the final momentum of wall 3.the rate of change of momentum 4.acceleration of the ball 5.the magnitude of force applied​

Answer 1

Answer:

according to me the mass of the ball should be 10 kg and here is the

m = 10 kg u = 50 m/s v = 70 m/

st=2s a = ?F= ? (a) Pi = m•u. = (10.50)kg m/s. = 500 kg m/s (b) Pf= m•v . = (10.70) kg m/s . = 700 kg m/s (c) a = (v-u)/t. = 10 m/s² (d) F = m•a . = 50kg x 10m/s². = 500 kg m/s². = 500N.

Answer 2

Answer:

0.5kg ms

Step-by-step explanation:

mass= 10g=10-²kg

Initial velocity, u = 50ms-¹

Initial momentum = mass x Initial velocity

= 10-² x 50

= 0.5kg ms