Question

a ball of mass 10 kg fall from tower 200 m hits ground come at rest after penetrating 100 cm find time

Answer 1

Answer:

Explanation:

To find time

We need to know the velocity with which ball hits the ground and the retardation of the ball while penetrating

Hence

From formula of motion

v²-u²=2as

v²=2as+u²

v²=2*10m/s²*200m+0

v=63m/s(approx)

This is the velocity with which the ball hits the ground

Retardation of ball=v²-u²/2s

=0-4000m²/s²/400m

=-10m/s²

Time taken for penetrating can be found by

v=u+at

0=63m/s- 10m/s²*t

t=6.3s(approx)

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