Question

A ball of mass 10 kg is moving with a velocity of 10 metre per second its right another ball of mass 5 kg which is moving in the same direction with a velocity of 4 metre per second if the collision is elastic their velocities after the collision for will be ​

Answer 1

Answer:

Net work is given by change in Kinetic energy

So, W = K2 - K1 = 1/2mv2^2 - 1/2mv1^2

From this it is already proved in the textbooks that

v1 = ((m1-m2/(m1+m2))u1 + (2m2/(m1+m2))u2

and v2 = (2m1/(m1+m2))u1 + ((m2-m1)/(m1+m2))u2

Putting the required values, we'll get,

v1 = ((10-5)/(10+5))x10 + (2x5/(10+5))x4

= 10/3 + 8/3 = 6m/s

v2 = (2x10/(10+5))x10 + ((5-10)/(10+5))x4

= 40/3 - 4/3

= 12m/s