Question

A ball of mass 10 kg is thrown upward with a velocity of 5m/s, what will be the value of its potential energy when it reaches to maximum height

Answer 1

hey, mate here is ur Ans.
taking the reference line "surface of ground"
S1. As conservative forces are only available so, by applying conservation of mechanical energy
k.e)1+p.e)1=k.e)2+p.e)2
1/2mv1^2+mgh1=1/2mv2^2+mgh2
h1=0 v2=0
v1=5m/s. m=10kg
so, mgh2=1/2(10)(5)
mgh2=25joule
h2 is max height

Answer 2

Answer:

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