Question

A ball of mass 100 g is dropped from a height of
60 m. What will be its kinetic energy at the height
of 30 m above the ground? [Take g = 10 m/s2)​

Answer 1

Answer:

30N

Explanation:

since K+U=E

1/2 of K + 1/2 of U = E at 30 mtrs,so mgx=1/2mv^2

mgx=30,

hence 1/2mv^2 is also 30