Physics, asked by raziazahoorwani, 1 month ago

A ball of mass 100 g strikes a wall normally with a
speed of 10 m/s and rebounds with the same speed
but in opposite direction. The magnitude of change
in linear momentum of the ball will be
(1) 2 kg m/s
(2) Zero
(3) 0.5 kg m/s
(4) 2000 kg m/s​

Answers

Answered by piyushkumarsharma797
3

this is your answer hope answer is useful

Attachments:
Answered by Itzheartcracer
2

Given :-

A ball of mass 100 g strikes a wall normally with a  speed of 10 m/s and rebounds with the same speed  but in opposite direction

To Find :-

Magnitude

Solution :-

We know that

1 kg = 1000 g

100 g = 100/1000 = 0.1 kg

Now

Initial momentum = Mass × Initial velocity

p₁ = m × u

p₁ = 0.1 × 10

p₁ = 1 kg m/s

Final momentum = Mass × Final velocity

Since, It move in opposite direction.

So v = -10 m/s

p₂ = m × v

p₂ = 0.1 × (-10)

p₂ = -1 kg m/s

Now

Δp = p₂ - p₁

Δp = -1 - 1

Δp = -2 kg/ms

Hence,

Option A is correct

Similar questions