A ball of mass 100 g strikes a wall normally with a
speed of 10 m/s and rebounds with the same speed
but in opposite direction. The magnitude of change
in linear momentum of the ball will be
(1) 2 kg m/s
(2) Zero
(3) 0.5 kg m/s
(4) 2000 kg m/s
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Given :-
A ball of mass 100 g strikes a wall normally with a speed of 10 m/s and rebounds with the same speed but in opposite direction
To Find :-
Magnitude
Solution :-
We know that
1 kg = 1000 g
100 g = 100/1000 = 0.1 kg
Now
Initial momentum = Mass × Initial velocity
p₁ = m × u
p₁ = 0.1 × 10
p₁ = 1 kg m/s
Final momentum = Mass × Final velocity
Since, It move in opposite direction.
So v = -10 m/s
p₂ = m × v
p₂ = 0.1 × (-10)
p₂ = -1 kg m/s
Now
Δp = p₂ - p₁
Δp = -1 - 1
Δp = -2 kg/ms
Hence,
Option A is correct
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