Question

a ball of mass 100g is dropped from height of 100m calculate it potential and kinetic energy at end of 3 second​

Answer 1

Answer:

P.E.=m gh

= 100/1000 × 10 × h

= h=ut+1/2gt^2

h=0× t+1/2 ×10 × 3^3

= 45

putting the values

mgh=100/1000 × 10 × 45

=45 joules

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Answer 2

Answer:

After 3 s,

v = u + at

= 30 m/ s

Kinetic energy = 1/2 mv^2

= 0.1* (30)^2/2

= 45 J

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