a ball of mass 100g is moving with velocity 10m/s is stopped by a boy in 0.25 calculate force applied to stop the ball
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Answered by
3
F=-ma
F=-m×v/t
F=-100×10/0.25
F=-1000/0.25
F=-1000/25/100
F=-1000/1/4
F=-1000*4
F=-4000N is answer
F=-m×v/t
F=-100×10/0.25
F=-1000/0.25
F=-1000/25/100
F=-1000/1/4
F=-1000*4
F=-4000N is answer
gsggsh:
in which class do you read ?
gsggsh u are under low in basics and u are commenting on us get lost
in which class do you read ?
10
or 11
or phd in physics ????
get lost
you are wrong
please show my mistake
if i am wrong show my mistake
Answered by
4
Given mass, m =100g Initial velocity, u = 10m/s Final velocity, v = 0 m/s [becuz it was stopped] Time, t = 0.25 s Force = mass × acceleration [newtons 2nd law of motion] Acceleration = v-u/t = 0-10/0.25 = -40 m/s Now, F= ma = 100 × (-40) = -4000 N Thats ur answer
wrong
it's correct
shut up
please check
thanks for ur answer harshita006
it's ok
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