Question

A ball of mass 100g moving with a velocity of 0m/s is stopped by a boy in 0.2s calculate the force applied by the boy to stop the ball Solve the numericals

Answer 1

Answer:

Explanation:

Correct Question,

A ball of mass 100 g is moving with a velocity 10 m/s is stopped by a boy in 0.2 seconds. Calculate the force applied by the boy to stop the ball.

Solution,

Here, we have

Mass of ball, m = 100 g = 0.1 kg

Initial velocity of ball, u = 10 m/s

Final velocity of ball, v = 0 (As ball stops)

Time taken, t = 0.2 seconds

To Find,

Force applied, F = ??

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ 0 = 10 + a × 0.2

⇒ - 10 = 0.2a

⇒ - 10/0.2 = a

⇒ a = - 50 m/s²

Here, the acceleration is - 50 m/s².

Now, We know that,

F = ma

So, putting all the values again, we get

⇒ F = ma

⇒ F = 0.1 × (- 50)

⇒ F = - 5 Newton.

Hence, the force applied by the boy to stop the ball is - 5 Newton.

Answer 2

Correct Question :-

⋄ A ball of mass 100g moving with a velocity of 10m/s is stopped by a boy in 0.2s calculate the force applied by the boy to stop the ball .

Given:-

• Initial velocity of ball (u) =10m/s

• Final velocity of ball (v) =0m/s

• Time taken to stop (t) =0.2s

• Mass of Ball (m) =100g=100/1000=0.1kg

To Find:-

• Force (f) applied by the boy to stop ball.

Solution :-

We know that the Force is the product of mass and acceleration

So, we have to find acceleration

By using 1st equation of motion

☛ v= u+at

☛ 0=10+a× 0.2

☛ a=10/0.2

☛a =50m/s²

∴ The acceleration of ball is 50m/s²

Now,

☛ Force =Mass × Acceleration

☛ F =ma

☛ F =0.1×50

☛F =5 N

∴The Force applied by boy to stop ball is 5N.