Question

A ball of mass 100g moving with velocity of 10m/s is stopped by a boy in 0.2 seconds.Calculate the force applied by the boy to stop the ball

Answer 1

F=mv/t=100/1000×10/.2=10/2=5 N

Answer 2

m=100g

u=10m/s

v=0m/s

t=0.2sec

to find force we will apply the formula F=m[v-u]\t as the acceleration is not given.

F=m[v-u]\t

F=100[0-10]\0.2

F=100[-10*10]\2

F=100[-100\2]

F=-1000\2

F=-500N