Question

A ball of mass 100kg moving with a velocity of 200m/s is brought to rest by a player in 0.1s. Find the impulse of the ball and the average force applied by the player . (PLEASE SOLVE IT WITH THE APPROPRIATE STEPS AND I WILL MARK YOU AS THE BRAINLIEST)

Answer 1

Answer:

2×10^4N/s

Explanation:

impulse =F×t

F=ma m=100kg v=200m/a t=0.1sec

F=mv/t

F=100×200/0.1

F=2×10^5= average force applied by the player

impulse =F×t

j or I =2×10^5×0.1

j or I =2×10^4 N/s