Question

A ball of mass 10g is moving with a velocity of 50 m/s on applying a constant force on ball for 2 sec. If acquires a velocity of 70 m/s calculate.​

Answer 1

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GIVEN THAT :-

• mass of the ball(m) = 10 g

• initial velocity of ball ( u ) = 50 m/s

• Final velocity of the ball (v) = 70 m/s

• time (t) = 2 second

EQUATION OF MOTION

1• V = U + at

2 • F = Ma

SOLUTION :-

V = U + at

$&#10143 \: \: 70 = 50 + a(2) \\ \\ &#10143 \: \: 2a = 70 - 50 \: \: \: \\ \\ &#10143 \: \: a = \frac{\cancel{20}}{\cancel2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ &#10143 \: \: a = 10 \: m {s}^{ - 2} \: \: \: \:$

Now F = ma

$&#10143 \: \: f = \frac{\cancel{10}}{10\cancel{00}} \times \cancel{10} \\ \\ &#10143 \: \: f = 0.1 \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Answer 2

Answer:

1. Momentum initial 0.5 Kg m/s

2. Momentum Final 0.7 Kg m/s

3. Rate of change of momentum 0.1 Kg m/s^2

4. Acceleration 10 m/s^2

Explanation: