Question

A ball of mass 10kg collides the vertical wall at an angle
30° with horizontal, with the velocities 5m/s and rebounds
with the same velocity and same angle then the change in
magnitude of momentum..... N-sec​

Answer 1

Answer:This may help you

Explanation:

Let their velocities after the collision be v

1

​

and v

2

​

. As we know for elastic collision.

Relative velocity of approach = relative velocity of separation

10−4=v

2

​

−v

1

​

⇒6=v

2

​

−v

1

​

⇒v

1

​

=v

2

​

−6

Applying conservation of momentum,

10×10+5×4=10v

1

​

+5v

2

​

120=10v

1

​

+5v

2

​

120=10(v

2

​

−6)+5v

2

​

=15v

2

​

−60

15v

2

​

=180⇒v

2

​

=12cm/sec

v

1

​

=6cm/sec