Question

a ball of mass 10pg is moving with a velocity of 10m/s2 is stopped by boy in 0.25sec. Calculate the force applied by the boy to stop the ball.

Answer 1

$\boxed{ \mathbf {Hey \: there}}$

• Given :-

•Mass of the ball , m = 10 kg

• initial velocity , u = 10 m/s

•final velocity , V = 0 m/s

We know -

$\boxed {\bf Force = Mass × Acceleration ...( 1 ) } \\ \\ \boxed{ \bf Acceleration = \frac{v - u}{t} } \\ \\ \ \: \Rightarrow \: a = \frac{0 - 10 \times 10}{25} \\ \\ \Rightarrow \: \boxed {\bf \: a = - 4 \: m {s}^{ - 2}...(2) }$
Putting ( 2 ) in equation ( 1 )

we get -

$\boxed {\bf force = 10 \times - 4 \Rightarrow \: - 40N }$

Hope this helps you ☺