Question

A ball of mass 120 g travelling with velocity 10 m/s at an angle 60° with a smooth wall collides with the wall. If immediately after the collision, the ball travels in a direction perpendicular to its initial direction

Answer 1

Answer:

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Answer 2

The answer to this quesiton is:

Explanation:

Mass of the ball will be 100 gm=0.1 kg

The velocity of the ball prior to collision will be 10m/s

The momentum of the ball prior to collision will be p(i)=mv-0.1x10=1 kgm/s

That since it is assumed that the ball shall come back with the same velocity

Hence, velocity of the ball post collision = -10 m/s (-ve sign because of opposite direction)

Therefore, the momentum of the ball post collision will be, p(f) = 0.1 x(-10) = -1 kgm/s

The impulse created in the ball will be equal to the change in momentum = p(f)-p(i)= -1–1= -2 kgm/s