A ball of mass 150 g moves with 12 m/s and bounces back after hitting a wall with 20 m/s after a small duration of 0.01 sec. Calculate the force applied to the ball when it hits the wall. SHOW IN A PHOTO WITH CLEAR SOLUTION
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Given:-
- Mass of ball (m) = 150g
- Initial velocity (u) = 12m/s
- Final velocity (v) = 20m/s
- Time taken (t) = 0.01s
To Find:-
- Force applied on the ball (F) .
Solution:-
As we know that acceleration is the rate of change of velocity at per unit time .
→ a = v-u/t
Substitute the value we get
→ a = 20-12/0.01
→ a = 8/0.01
→ a = 800m/s²
And Now Force is defined as the product of mass and acceleration.
→ F = m×a
Substitute the value we get
→ F = 150/1000×800
→ F = 0.15 ×800
→ F = 120N
∴ The force applied on the ball is 120 Newton.
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