Question

A ball of mass 150 g, moving with an acceleration
20 m/s², is hit by a force, which acts on it for
0.1 sec. The impulsive force is
(a) 0.5 N (b) 0.1 N
(c) 0.3 N (d) 1.2 N

Answer 1

Answer:

• The Impulsive Force on the ball is 0.3 Kg-m/s

Given:

1. Mass of the ball (M) = 150 grams.
2. Acceleration (a) = 20 m/s².
3. Time Period of contact (t) = 0.1 Sec.

Explanation:

$\rule{300}{1.5}$

From the relation we know,

⇒ F = M a

Where,

• F Denotes Force.
• M Denotes Mass.
• a Denotes Acceleration.

Now,

⇒ F = M a

Substituting the values,

⇒ F = 150 grams × 20 m/s²

∵ [ 1 gram = 10⁻³ Kg ]

∴ [ 150 grams = 150 × 10⁻³ = 0.15 Kg]

Substituting,

⇒ F = 0.15 Kg × 20 m/s²

⇒ F = 0.15 × 20

⇒ F = 3

⇒ F = 3 N.

$\rule{300}{1.5}$

$\rule{300}{1.5}$

From the relation we know,

⇒ I = F × t

Where,

• F Denotes Force.
• I Denotes Impulse.
• t Denotes time of contact.

Now,

⇒ I = F × t

Substituting the values,

⇒ I = 3 N × 0.1 sec

∵ [ F = 3 N ; t = 0.1 sec ]

⇒ I = 3 × 0.1

⇒ I = 0.3

⇒ I = 0.3 Kg-m/s

∴ The Impulsive Force on the ball is 0.3 Kg-m/s

Hence 3rd Option is Correct.

$\rule{300}{1.5}$

Answer 2

Answer:

Impulsive force I=F*Δt

                           =.15*20*0.1

                           =0.3 N s

HOPE IT HELPS YOU