Question

a ball of mass 150 gm.going
at a speed of 20ms is hit
by a bat if it moves back with the same velocity. FIND CHANGE IN ITS MOMENTUM??
A) 65kg.ms-1
B) 6kg.ms-1
C) 7kg.ms-1
D) 60kg.ms-1​

Answer 1

Mass of the ball (m) = 150 g = 0.15 kg

Initial velocity of the ball (u) = 20 m/s

Final velocity of the ball (v) = - 20 m/s

Note : - ve sign shows that velocity of the ball is in opposite direction to it's initial velocity

_______________________________

★ Momentum (P) : It is given by the product of mass and velocity

➡ P = mv

➡  It is vector quantity having both direction and magnitude

➡  May be zero or negative or positive

➡  SI units : Kg-m/s

★ Change in momentum (ΔP) : It is given by the product of mass and change in velocity

➽ ΔP = MΔv

➽ ΔP = m ( v - u )

_______________________________

➠ ΔP = m ( v - u )

➠ ΔP = (0.15) (20 - ( - 20 ))

➠ ΔP = (0.15) (20 + 20)

➠ ΔP = (0.15)(40)

➠ ΔP = 6 kg-m/s  $\pink{\bigstar}$

Answer 2

Answer:

Mass of the ball (m) = 150 g = 0.15 kg

Initial velocity of the ball (u) = 20 m/s

Final velocity of the ball (v) = - 20 m/s

Note : - ve sign shows that velocity of the ball is in opposite direction to it's initial velocity

_______________________________

★ Momentum (P) : It is given by the product of mass and velocity

➡ P = mv

➡ It is vector quantity having both direction and magnitude

➡ May be zero or negative or positive

➡ SI units : Kg-m/s

★ Change in momentum (ΔP) : It is given by the product of mass and change in velocity

➽ ΔP = MΔv

➽ ΔP = m ( v - u )

_______________________________

➠ ΔP = m ( v - u )

➠ ΔP = (0.15) (20 - ( - 20 ))

➠ ΔP = (0.15) (20 + 20)

➠ ΔP = (0.15)(40)

➠ ΔP = 6 kg-m/s \pink{\bigstar}★