Question

A ball of mass 150 gram moving at velocity of 15 metre per second is brought to rest by a player in 0.1 second calculate the force acting on the hands of player

Answer 1

f= ma 
f= m ( v-u /t )
here u = 0 

f= m v /t 

f= 0.150 x 15 / 0.1 
f= 2.25 / 0.1 
f= 22.5 N

Answer 2

f =ma

f = m(v-u/t)

here u =0

f = m v/t

f=0.150 ×15/0.1

f = 2.25/0.1

f = 22.5N