A ball of mass 150g and velocity 12ms' coming towards a batsman is hit by him with a force of 480N
in such a way that ball moves with velocity 20ms' in the direction opposite to its original one. Find
the time of contact between the ball and the bat?
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Answer:
Impulse=F×t= Change in Momentum
⇒ Change in Momentum =mv−mu=0.15(12)−0.15(−20)=4.8
⇒F×0.001=4.8
⇒F=4800N
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