Question

a ball of mass 150g moving with a velocity of 15ms² is brought to rest by player in 0 is calculate the force acting on the hand of the player's​

Answer 1

Physics for class 9

Force and Laws of Motion

Question:

A ball of mass 150g is moving with a velocity of 15m/s is brought to rest by a player in 0.1s. Calculate the force acting on the hands of the player.

Answer:

Provided quantities:

Mass (m) = 150g = 0.15 kg

Initial Velocity (u) = 15 m/s

Final velocity (v) = 0 m/s

Time (t) = 0.1 s

Applying Newton's second law of motion:

F= ma

F = m $\frac{v-u}{t}$

F = 0.15 kg x $\frac{0-15}{0.1}$

(Removing the decimal point from the denominator, we have to multiply the numerator with 10.)

Therefore,

F = 0.15 x -150

F = -22.5 N

Therefore the force acting on the hand of the player is -22.5 N.

Know More

⩥ Newton's second law of motion states that the rate of change of momentum is directly proportional to the unbalanced external force applied  in the direction of motion.

⩥ The equation used is F=ma

To know more about Newton's second law motion and its application, refer to:

https://brainly.in/question/24991323