Question

a Ball of mass 1kg dropped from 9.8 m height, strikes the ground and rebounds to a height 4.9 m.if the time of contact between ball and ground is0.1 sec,then the find impulses and average force acting on ball.

Answer 1

Hi friend here is your answer

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Displacement=9.8-4.9=4.9 m
Mass=1 kg
Time=0.1 second

We know, F=ma, where a = acceleration
in this case a=g

F=mg=1×9.8=9.8 N

Impulse =Ft=9.8×0.1=0.98 Ns

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