A ball of mass 1kg is at a height of 20m above the ground. In free fall, find(i) speed of the ball when it reaches the ground and (ii) work done by the gravitational force. (Take g = 10ms).
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work done=mgh=1kg*20m*10m/squ..=200joule.
from work and energy theory.
velocity =√2gh=√2*10*20=√400=20m/s.
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work done=mgh=1kg*20m*10m/squ..=200joule.
from work and energy theory.
velocity =√2gh=√2*10*20=√400=20m/s.
...... Thanks Be always brainliest....
Answered by
8
Answer:Speed is 20m/s and work done is 200 joule
Explanation:
1) To find speed use the equation
v^2-u^2 = 2as
For gravitational force use g insted.
of and h instead of h
So the equation becomes
v^2-u^2 = 2gh
v^2-0^2 = 2*10*20
v^2 = 400
v = √400
v = 20
So v = 20m/s is the speed
2) work done = mgh
Work done = 1*10*20
Work done = 200
So the work done is 200 joule
Hope it works✌
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