A ball of mass 1kg is dropped from a height of 5m.(1) find the kinetic energy of the ball just before it reaches the ground. (2) what is its speed at this instant?
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Answered by
56
Hey Mate
your answer is here
let potential energy is zero at ground
then
potential energy at height 5m = mg = 1×10 = 10J
so ,
kinetic energy at ground = 10J
according to energy conversation law
so,
1/2mv^2 = 10
v^2 = 20
v = root 20 m/s
Be Brainly
your answer is here
let potential energy is zero at ground
then
potential energy at height 5m = mg = 1×10 = 10J
so ,
kinetic energy at ground = 10J
according to energy conversation law
so,
1/2mv^2 = 10
v^2 = 20
v = root 20 m/s
Be Brainly
Answered by
47
I'm sure about this answer
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