Physics, asked by samboy8582, 10 months ago

A ball of mass 1kg is moving with a velocity of 15m/sec undergoes head on elastic collision with another ball

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Answered by Anonymous
0

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Aristocles Ambitious

for elastic collision between two balls we can say momentum of two balls is conserved

P_{1i} + P_{2i} = P_{1f} + P_{2f}

now we have

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

0.1*v_{1i} + m_2*0 = 0.1*(-\frac{v_{1i}}{3}) + m_2v_{2f}

\frac{0.4v_{1i}}{3} = m_2v_{2f}

also for elastic collision we can say

v_{2f} - v_{1f} = v_{1i} - v_{2i}

v_{2f} - (-\frac{v_{1i}}{3}) = v_{1i} - 0

v_{2f} = \frac{2v_{1i}}{3}

now from above two equations

\frac{0.4v_{1i}}{3} = m_2* \frac{2v_{1i}}{3}

m_2 = 0.2 kg

so mass of other ball is 0.2 kg

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