A ball of mass 1kg moving at 2ms-1 hits another ball of mass 2kg moving at 1ms-1 in same direction after hitting the ball of mass 1kg starts to moves at 1ms-1 . Find the velocity of 2kg ball.
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Explanation:
Law of con. of momentum.
m
1
v
1
+m
2
v
2
=m
1
v
3
+m
2
v
4
1×21+2×(−4)=1×1+2v
v=6m/s
i.e, direction of B is reversed.
e=
vel.ofapproach
vel.ofseparation
=
21−(−4)
6−1
=0.2
loss in K.E.=
2
1
(1×21×21+2×4×4−1×1×1−2×6×6)=200J
impulse =2×6−2×
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