Question

A ball of mass 2 kg going with a velocity of 10 m/s collides with another stationery ball of
mass 3 kg. After the collision, the balls move with the same velocity ‘v’ in the original
direction. Find the value of ‘v’.

Answer 1

EXPLANATION :

Applying conservation of momentum,

m1 v1 = (m1 + m2)v

⟶ v = (m1 v1)/(m1 + m2)

Here,

• m1 = 2kg
• m2 = 3kg
• v1 = 10 m/s
• v = ?

[ Put the values ]

⟶ v = (2 × 10)/(2 + 3)

⟶ v = (20)/(5)

⟶ v = 4 m/s

Therefore,

The value of v is 4 m/s.

★Verification :

m1 v1 = (m1 + m2)v (Formula)

[ Put the values ]

⟶ 2 × 10 = (2 + 3) × 4

⟶ 20 = (5) × 4

⟶ 20 = 20

Hence Verified !!