A ball of mass 2 kg is dropped from a height of 5 m. On striking the ground it rebounds with same speed
with which it struck the ground. Find the magnitude of net change in its momentum just after striking
the ground. [Take, g = 10 m/s?]
Answers
Answered by
6
Answer:
2m√2gh which is equal to 40Ns
Answered by
0
Answer:
2√2 mgh = 40 Newton
Force = 40 N
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