A ball of mass 2 kg is dropped from a height of 5 m. On striking the ground it rebounds with same speed
with which it struck the ground. Find the magnitude of net change in its momentum just after striking the
ground. [Take, g = 10 m/s2
]
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Answer:
100 joules
Explanation:
- P.E = mgh
- m=2kg. h =5m
- PE= 2* 10* 5 =100 J
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